Combined Gas Law Calculator

Solve for pressure, volume, or temperature with the combined gas law (P1V1/T1 = P2V2/T2).
Enter any five values in consistent units to get the sixth.

Result

The Combined Gas Law merges Boyle’s Law, Charles’s Law, and Gay-Lussac’s Law into a single relationship that describes how pressure, volume, and temperature of a fixed amount of gas interact.

The formula:

(P₁ × V₁) / T₁ = (P₂ × V₂) / T₂

Where:

  • P₁, P₂ = Initial and final pressure (must be in absolute units: kPa, atm, or psia, NOT gauge pressure)
  • V₁, V₂ = Initial and final volume (any consistent unit: L, mL, m³, ft³, gallons)
  • T₁, T₂ = Initial and final temperature in Kelvin (K = °C + 273.15, or K = (°F + 459.67) × 5/9)

Critical note on Kelvin:

Temperature MUST be in Kelvin for this formula to work. Using Celsius or Fahrenheit will give wrong results. Kelvin starts at absolute zero (−273.15°C = −459.67°F), where gas molecules theoretically have zero kinetic energy.

The three sub-laws:

  • Boyle’s Law (isothermal, T constant): P₁V₁ = P₂V₂, pressure and volume are inversely proportional
  • Charles’s Law (isobaric, P constant): V₁/T₁ = V₂/T₂, volume and temperature are directly proportional
  • Gay-Lussac’s Law (isochoric, V constant): P₁/T₁ = P₂/T₂, pressure and temperature are directly proportional

Practical examples:

  1. Car tire heating: A tire inflated to 32 psi (gauge) at 20°C, what pressure at 60°C?

    • P₁ = 32 + 14.7 = 46.7 psia; T₁ = 293 K; T₂ = 333 K
    • P₂ = 46.7 × 333/293 = 53.1 psia = 38.4 psi gauge
  2. Scuba tank: A tank filled to 3,000 psi (gauge) at 25°C, taken into −5°C water?

    • P₁ = 3,000 + 14.7 = 3,014.7 psia; T₁ = 298 K; T₂ = 268 K
    • P₂ = 3,014.7 × 268/298 = 2,711 psia = 2,697 psi on the gauge, about 10% down
    • At tank pressures the 14.7 moves the answer by about a psi, which is why divers skip it. On the tyre above it is almost a third of the absolute pressure, and skipping it there gives 36.4 psi instead of 38.4.

Metric pressure units:

  • 1 atm = 101.325 kPa = 14.696 psi
  • Standard conditions (STP): 0°C (273.15 K) and 1 atm (101.325 kPa), the older definition most textbooks still use. IUPAC has defined STP at 100 kPa since 1982.
  • SATP: 25°C (298.15 K) and 100 kPa

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This calculator runs entirely in your browser, so the numbers you enter stay on your device. The math behind it is written by hand and tested against worked examples and standard references before the page goes live.

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