Redox Reaction Calculator

Calculate cell potential, Gibbs free energy change, and equilibrium constant for a redox cell.
Enter standard reduction potentials for the cathode and anode.

Redox Reaction

In an electrochemical cell, the cathode is where reduction occurs (gain of electrons) and the anode is where oxidation occurs (loss of electrons). Both half-reactions are tabulated as reduction potentials measured against the standard hydrogen electrode.

The cell potential under standard conditions is: E_cell = E_cathode - E_anode. Both values are taken as reduction potentials. The minus sign accounts for the fact that the anode reaction runs in reverse (as an oxidation). If E_cell > 0, the reaction is spontaneous under standard conditions.

For the classic copper-zinc (Daniell) cell: copper cathode E = +0.34 V, zinc anode E = -0.76 V. Cell potential = 0.34 - (-0.76) = 1.10 V. This is the familiar battery voltage for a Zn/Cu cell.

The relationship to Gibbs free energy is: delta_G = -n * F * E_cell, where n is the number of electrons transferred and F is Faraday’s constant (96485 C/mol). A positive E_cell gives a negative delta_G, confirming spontaneity. delta_G is in joules; divide by 1000 for kilojoules.

The equilibrium constant K at temperature T is: K = exp(n * F * E_cell / (R * T)), where R = 8.314 J/(mol*K). At standard temperature (298.15 K), this simplifies to log(K) = n * E_cell / 0.05916 (in base 10). A large positive E_cell drives K toward very large values, meaning the reaction goes nearly to completion.

The Nernst equation adjusts E for non-standard concentrations: E = E_cell - (RT / (nF)) * ln(Q), where Q is the reaction quotient. At equilibrium, Q = K and E = 0.

Reduction potentials are intrinsic to the half-reaction, not the cell. You can always reverse a half-reaction to make it an oxidation, but you must flip the sign of its potential when you do.


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