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Van't Hoff Factor Calculator

Calculate the Van't Hoff factor i from experimental freezing point depression or from degree of dissociation α.
Understand how electrolytes affect colligative properties.

Van't Hoff Factor

The Van’t Hoff factor (i) accounts for the fact that some solutes dissociate or associate when dissolved, changing the number of particles in solution.

Definition:

i = (actual number of particles in solution) / (number of formula units dissolved)

For non-electrolytes (glucose, sucrose, urea): i = 1

For electrolytes (theoretical, complete dissociation):

  • NaCl → Na⁺ + Cl⁻: i = 2
  • MgCl₂ → Mg²⁺ + 2Cl⁻: i = 3
  • AlCl₃ → Al³⁺ + 3Cl⁻: i = 4
  • K₂SO₄ → 2K⁺ + SO₄²⁻: i = 3

Experimental determination from colligative properties:

From freezing point depression: i = ΔTf_observed / (Kf × m)

From boiling point elevation: i = ΔTb_observed / (Kb × m)

From osmotic pressure: i = π_observed / (MRT)

Relationship to degree of dissociation α:

For a compound that dissociates into n ions: i = 1 + α(n - 1)

Solving for α: α = (i - 1) / (n - 1)

Why i < theoretical for electrolytes? At higher concentrations, oppositely charged ions tend to cluster (ion pairing), reducing the effective number of particles. This is why the experimental i is always ≤ the theoretical value.

Example — 0.1 m NaCl:

  • Theoretical i = 2 (complete dissociation)
  • Experimental i ≈ 1.87 (some ion pairing)
  • α = (1.87 - 1)/(2 - 1) = 0.87 (87% dissociated effectively)

Colligative property formulas with i:

  • Freezing point depression: ΔTf = i × Kf × m
  • Boiling point elevation: ΔTb = i × Kb × m
  • Osmotic pressure: π = i × MRT
  • Vapor pressure lowering: ΔP = i × x_solute × P°

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