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Isosceles Triangle Perimeter Calculator

Compute isosceles triangle perimeter from the base and the two equal legs.
Validates triangle inequality.
Multiple units.

Perimeter

An isosceles triangle has two equal legs (s) and one different base (b).

P = b + 2s

A triangle with 6 cm base and 5 cm legs has perimeter 6 + 10 = 16 cm.

Validity check: for the triangle to close, the legs must each be longer than half the base (s > b/2). If s = b/2 exactly, the “triangle” collapses to a straight line of length b. If s < b/2, no triangle is possible.

Where isosceles triangles show up in real measurements:

  • Party pennants and bunting. A standard bunting pennant is isosceles. A 6 in base × 8 in legs has perimeter 22 in. Twenty pennants need 440 in (~37 ft) of edge trim or rope.
  • Pizza slices approximate isosceles triangles when the pizza is cut into equal slices. An 8-slice 16-inch pizza yields slices with about 6-in equal legs and a 6.1-in base (the curved crust edge approximated as straight).
  • Mainsail sailmaking. Most sailing mainsails are roughly isosceles triangles when the boom is horizontal — luff (vertical edge, fixed length) ≈ leech (slanted trailing edge), with foot as the base.
  • Roof rafters. Symmetric gable roofs are isosceles triangles in cross-section. Two equal rafter lengths plus the building width.
  • Triangular flags. Most pennant flags are isosceles.

Worked example — bunting for a backyard party:

You’re making 25 pennants with 5-in bases and 7-in legs. Each pennant perimeter = 5 + 14 = 19 in. Total edge to hem = 25 × 19 = 475 in ≈ 40 ft of edge.

For the connecting string, you need 25 pennants × 5 in (top of pennant base) = 125 in of stringing, plus extra for tying between pennants. Buy a 40-ft roll of party string.

Worked example — flagpole pennant:

A nautical signal pennant with a 12 in base and 36 in legs (long, narrow shape). P = 12 + 72 = 84 in. Edge tape needed: 90 in (allowing for corner reinforcement).

Quick relations from base b and leg s:

  • Perimeter: P = b + 2s
  • Height (from apex perpendicular to base): h = √(s² − (b/2)²)
  • Area: A = ½ × b × h = ½ × b × √(s² − b²/4)

Special case 1: when b = s, the triangle is equilateral. P = 3s. Special case 2: when b = s × √2, the apex angle is 90° — you have an isosceles right triangle.

If you only know two angles (say the apex angle θ) and the base, the leg length is s = b / (2 × sin(θ/2)). Then plug into the perimeter formula.


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