Fermi Energy Calculator
Calculate the Fermi energy of a metal from its electron number density.
Shows Fermi energy in eV and Fermi temperature.
Includes presets for common metals.
The Fermi energy is the highest occupied electron energy level in a metal at absolute zero temperature:
E_F = (ħ²/2m_e)(3π²n)^(2/3)
Fermi temperature: T_F = E_F / k_B
Where:
- E_F = Fermi energy (joules)
- ħ = Reduced Planck constant = 1.0546 × 10⁻³⁴ J·s
- m_e = Electron mass = 9.109 × 10⁻³¹ kg
- n = Free electron number density (electrons/m³)
- k_B = Boltzmann constant = 1.381 × 10⁻²³ J/K
Fermi energy of common metals:
| Metal | n (×10²⁸ /m³) | E_F (eV) | T_F (K) |
|---|---|---|---|
| Lithium | 4.70 | 4.74 | 55,000 |
| Sodium | 2.65 | 3.24 | 37,600 |
| Aluminum | 18.1 | 11.7 | 135,800 |
| Copper | 8.49 | 7.04 | 81,700 |
| Gold | 5.90 | 5.53 | 64,200 |
| Silver | 5.86 | 5.49 | 63,700 |
Why Fermi energy matters:
The Fermi energy is critical for understanding:
- Electrical conductivity: Only electrons near E_F can be excited into higher states by an applied voltage. Metals conduct because E_F lies in the middle of an energy band.
- Thermoelectric effects: The Seebeck coefficient depends on the density of states near E_F
- X-ray emission: When electrons fall back to fill inner shell vacancies, they emit X-rays with energies related to E_F
- White dwarf stars: The Fermi energy of degenerate electrons supports the star against gravitational collapse
The Fermi temperature T_F is typically ~50,000–100,000 K — far above room temperature. This is why electrons in metals are highly degenerate (quantum effects dominate) even at room temperature.