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Stress-Strain Formula

Calculate stress, strain, and Young's modulus for materials under load.
Essential for structural analysis and material selection.

The Formulas

Stress (sigma) = F / A

Strain (epsilon) = deltaL / L₀

Young's Modulus: E = sigma / epsilon

Stress measures the internal force per unit area within a material. Strain measures how much the material deforms relative to its original length.

Young's modulus (E) links stress and strain in the elastic region. A higher Young's modulus means the material is stiffer and resists deformation more strongly.

Variables

SymbolMeaningUnit
sigma (stress)Force per unit areapascals (Pa) or N/m²
FApplied forcenewtons (N)
ACross-sectional area
epsilon (strain)Relative change in lengthdimensionless
deltaLChange in lengthm
L₀Original lengthm
EYoung's modulus (modulus of elasticity)Pa or GPa

Common Young's Modulus Values

MaterialYoung's ModulusCategory
Steel200 GPaVery stiff
Aluminum69 GPaStiff
Copper117 GPaStiff
Concrete30 GPaModerate
Wood (oak)12 GPaFlexible
Rubber0.01-0.1 GPaVery flexible

Example 1 — Steel Rod Under Tension

A steel rod has a cross-sectional area of 0.001 m² and is pulled with a force of 50,000 N. Find the stress and the elongation if the rod is 2 m long. (E for steel = 200 GPa)

Step 1: Stress = F / A = 50,000 / 0.001 = 50,000,000 Pa = 50 MPa

Step 2: Strain = stress / E = 50,000,000 / 200,000,000,000 = 0.00025

Step 3: deltaL = strain x L₀ = 0.00025 x 2 = 0.0005 m

Stress = 50 MPa, Elongation = 0.5 mm

Example 2 — Comparing Materials

An aluminum wire and a steel wire have the same dimensions (1 mm² cross-section, 1 m long). Both carry a 100 N load. Compare their elongation.

Stress = F / A = 100 / 0.000001 = 100 MPa (same for both)

Steel: strain = 100,000,000 / 200,000,000,000 = 0.0005 -> deltaL = 0.5 mm

Aluminum: strain = 100,000,000 / 69,000,000,000 = 0.00145 -> deltaL = 1.45 mm

The aluminum wire stretches about 2.9 times more than the steel wire

When to Use It

Use the stress-strain formula when:

  • Selecting materials for structural components that must support specific loads
  • Calculating how much a beam, rod, or cable will stretch or compress
  • Determining if a material will stay within its elastic limit under a given force
  • Comparing stiffness of different materials for engineering design
  • Analyzing failure modes in mechanical and civil engineering

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