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Coefficient of Restitution Formula

Calculate how elastic a collision is using the coefficient of restitution.
Ranges from 0 (perfectly inelastic) to 1 (perfectly elastic).

The Formula

e = (v₂' − v₁') / (v₁ − v₂)

The coefficient of restitution (e) measures how much kinetic energy is retained after a collision. It is defined as the ratio of the relative speed after impact to the relative speed before impact. A value of 1 means no kinetic energy is lost (perfectly elastic). A value of 0 means the objects stick together (perfectly inelastic).

Variables

SymbolMeaningUnit
eCoefficient of restitution (0 to 1)dimensionless
v₁Velocity of object 1 before collisionm/s
v₂Velocity of object 2 before collisionm/s
v₁'Velocity of object 1 after collisionm/s
v₂'Velocity of object 2 after collisionm/s

For a ball dropped from height h₀ that bounces to height h₁:

e = √(h₁/h₀)

Typical values: steel ball on steel plate ≈ 0.6–0.7, rubber ball ≈ 0.8, tennis ball ≈ 0.74, golf ball ≈ 0.7, perfectly inelastic collision (clay) ≈ 0.

Example 1 — Bouncing Ball

A rubber ball is dropped from 1.0 m and bounces back to 0.64 m. Find the coefficient of restitution.

e = √(h₁/h₀) = √(0.64/1.0)

e = √0.64

e = 0.8 — this ball retains 80% of its speed (and 64% of its kinetic energy) after each bounce

Example 2 — Two-Body Collision

A 2 kg ball moving at 5 m/s strikes a stationary 3 kg ball. The coefficient of restitution is 0.7. Find final velocities.

Using conservation of momentum: m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

2×5 + 3×0 = 2v₁' + 3v₂' → 2v₁' + 3v₂' = 10 ... (1)

Restitution: e = (v₂' − v₁')/(v₁ − v₂) = 0.7 → v₂' − v₁' = 0.7×5 = 3.5 ... (2)

From (2): v₂' = v₁' + 3.5. Substituting in (1): 2v₁' + 3(v₁' + 3.5) = 10 → 5v₁' = −0.5 → v₁' = −0.1 m/s

v₁' = −0.1 m/s (bounces back), v₂' = 3.4 m/s (moves forward)

When to Use It

Use the coefficient of restitution when:

  • Analyzing ball sports — basketball, tennis, squash, golf, and cricket all have regulated COR values
  • Designing impact-absorbing materials and protective packaging
  • Engineering collision safety systems in vehicles
  • Studying granular materials and powder behavior
  • Calculating multi-bounce trajectories in billiards or pinball machines

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