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Stefan-Boltzmann Law

Calculate total radiated power from a blackbody using temperature.
Stefan-Boltzmann law explained with examples.

The Formula

P = ε × σ × A × T⁴

The Stefan-Boltzmann law states that the total energy radiated per unit time by a body is proportional to the fourth power of its absolute temperature. A small increase in temperature causes a dramatic increase in radiated power.

For a perfect blackbody, the emissivity ε = 1. Real objects have ε between 0 and 1 depending on their surface properties.

Variables

SymbolMeaningUnit
PTotal radiated powerwatts (W)
εEmissivity of the surface (0 to 1)dimensionless
σStefan-Boltzmann constant (5.67 × 10⁻⁸ W/m²K⁴)W/m²K⁴
ASurface area of the radiating body
TAbsolute temperatureKelvin (K)

Example 1

Calculate the power radiated by the Sun (radius ≈ 6.96 × 10⁸ m, T ≈ 5778 K)

Surface area A = 4π × (6.96 × 10⁸)² ≈ 6.09 × 10¹⁸ m²

Assume ε = 1 (blackbody approximation)

P = 1 × 5.67 × 10⁻⁸ × 6.09 × 10¹⁸ × (5778)⁴

T⁴ = (5778)⁴ ≈ 1.115 × 10¹⁵

P ≈ 3.85 × 10²⁶ W — matches the Sun's known luminosity

Example 2

A steel plate (ε = 0.6, area = 2 m²) at 500 K. How much power does it radiate?

P = 0.6 × 5.67 × 10⁻⁸ × 2 × (500)⁴

T⁴ = 500⁴ = 6.25 × 10¹⁰

P = 0.6 × 5.67 × 10⁻⁸ × 2 × 6.25 × 10¹⁰

P ≈ 4,253 W (about 4.25 kW)

When to Use It

  • Estimating heat loss from hot surfaces by thermal radiation
  • Calculating stellar luminosity from surface temperature
  • Designing thermal insulation and radiative cooling systems
  • Climate science — modeling Earth's energy balance
  • Industrial furnace and kiln engineering

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